Answered

a car has a velocity of 10 m/s at new acceleration of 1 m/s2 for 30 seconds. 1. find the distance travelled and the final velocity of that car



Answer :

Answer:

final velocity is 40 m/s

the distance travelled is 750m

Explanation:

the distance travelled is 750m

From v = u + at

v = 10 + 1 × 30

v = 10 + 30

v = 40 m/s

Therefore, final velocity is 40 m/s

Also From equation of motion:

v^2 = u^2 + 2as then

[tex]s = \frac{ {v}^{2} - {u}^{2} }{2a} = \frac{ {40}^{2} - {10}^{2} }{2 \times 1} [/tex]

[tex] = \frac{(40 - 10)(40 + 10)}{2} [/tex]

[tex] = \frac{30 \times 50}{2} = 15 \times 50[/tex]

= 750m

Therefore, the distance travelled is 750m