Answer:
Step-by-step explanation:Let's denote the number of years from now as \( x \). In \( x \) years, the daughter will be \( 10 + x \) years old, and the mother will be \( 36 + x \) years old.
According to the problem, the mother's age in \( x \) years will be twice the daughter's age in \( x \) years. Mathematically, we can represent this as:
\[ 36 + x = 2(10 + x) \]
Now, let's solve for \( x \):
\[ 36 + x = 20 + 2x \]
Subtract 20 from both sides:
\[ 16 + x = 2x \]
Subtract \( x \) from both sides:
\[ 16 = x \]
So, in 16 years, the mother will be twice her daughter's age.
Answer:
16 years
Step-by-step explanation:
Right now daughter's age is 10
Right now mom's age is 36
Let x be the number of years that elapses from now when mom's age = 2 times daughter's age
Putting this in algebraic terms
mother's age in x years = 2 * daughter's age in x years
36 + x = 2 (10 + x)
Expand parens
36 + x = 20 + 2x
36 - 20 = 2x - x
16 = x
So in 16 years, mom will be twice as old as daughter now
Check
Daughter in 16 years = 10 + 16 = 26
Mother in 16 years = 36 + 16 = 52
52/26 = 2