How many moles of gas does it take to occupy 120 L at a pressure of 2.3 ATM and the temperature of 340 K(9.89 moles)

How many moles of gas does it take to occupy 120 L at a pressure of 23 ATM and the temperature of 340 K989 moles class=


Answer :

Answer:

Explanation:

To calculate the number of moles of gas that occupy a given volume at a certain pressure and temperature, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Given:

Pressure (P) = 2.3 ATM

Volume (V) = 120 L

Temperature (T) = 340 K

We can rearrange the ideal gas law equation to solve for the number of moles (n):

n = PV / RT

Plugging in the values:

n = (2.3 ATM 120 L) / (0.0821 LATM/molK 340 K)

n = 276 / 27.914

n ≈ 9.89 moles

Therefore, the number of moles of gas that occupy 120 L at a pressure of 2.3 ATM and a temperature of 340 K is approximately 9.89 moles.

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