Here's how to determine the number of offspring with vestigial wings in a cross between two first-generation (NN) individuals, assuming vestigial wings are recessive (nn) and long wings are dominant (NN orNn).
* Punnett Square Setup: Since both parents are NN (heterozygous with long wings), we can use a Punnett square to determine the genotypic probabilities of their offspring.
| | N | N |
|---|---|---|
| N | NN | Nn |
| N | Nn | NN |
* Genotype Analysis:
* NN: Offspring with this genotype will have long wings (dominant).
* Nn: Offspring with this genotype will also have long wings (dominant).
* Recessive Trait Probability:
* Since vestigial wings (nn) are recessive and neither parent has that genotype, none of the offspring (0) will have vestigial wings in this specific cross.
Therefore, out of 300 offspring, none (0) would be expected to have vestigial wings.
Important Note: This scenario assumes complete dominance and disregards the possibility of genetic variations. Real-world genetics can sometimes be more complex.
