Answer:
To prove AACD ≅ ABCD, we can use the SAS (Side-Angle-Side) postulate, which states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the triangles are congruent.
Given:
- AC ≅ BC
- ∠ACD ≅ ∠BCD
- CD ≅ CD (Reflexive Property)
Statements:
1.) AC ≅ BC and D is the midpoint of B
2.) ∠ACD ≅ ∠BCD (Given)
3.) CD ≅ CD (Reflexive Property)
Reasons:
1.) Given
2.) Given
3.) Reflexive Property
By the SAS postulate, we can conclude that triangle AACD ≅ triangle ABCD.
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