Answer:
AB = 5√5, Gradient of AC = -3/7, Inclination of AC ≈ -22.62°, Magnitude of BCD = √13
Step-by-step explanation:
Use the distance formula to find AB: AB = √((10-0)^2 + (2-7)^2) = √(100 + 25) = √125 = 5√5
Find the gradient of AC using (y2-y1)/(x2-x1): m = (4-7)/(7-0) = -3/7
Calculate the angle of inclination θ using tan(θ) = m: θ = arctan(-3/7) ≈ -22.62°
Find the magnitude of BCD using the distance formula: BCD = √((10-7)^2 + (2-4)^2) = √9 + 4 = √13