Answer :
Sure, let's calculate the distance the chariot travels step by step.
1. Understanding the Problem:
- We know the diameter of the wheel is 2 meters.
- The wheel rotates 120 times.
- We need to find the distance traveled by the chariot if the wheel rotates this many times.
2. Calculate the Circumference of the Wheel:
- The circumference [tex]\( C \)[/tex] of a circle (which the wheel is) is given by the formula:
[tex]\[ C = \pi \times d \][/tex]
where [tex]\( d \)[/tex] is the diameter.
3. Given:
- Diameter ([tex]\( d \)[/tex]) = 2 meters,
- Pi ([tex]\( \pi \)[/tex]) is approximately 3.1416.
4. Substitute the Values:
[tex]\[ C = \pi \times 2 \approx 3.1416 \times 2 = 6.2832 \text{ meters} \][/tex]
5. Calculate the Distance Traveled after 120 Rotations:
- If the wheel rotates 120 times, the total distance traveled [tex]\( D \)[/tex] can be found by multiplying the circumference of the wheel with the number of rotations.
[tex]\[ D = C \times \text{number of rotations} \][/tex]
[tex]\[ D = 6.2832 \times 120 = 753.984 \text{ meters} \][/tex]
6. Approximate the Answer:
- The closest option to 753.984 meters is 753.6 meters.
So, the correct answer is:
B. 753.6 meters
1. Understanding the Problem:
- We know the diameter of the wheel is 2 meters.
- The wheel rotates 120 times.
- We need to find the distance traveled by the chariot if the wheel rotates this many times.
2. Calculate the Circumference of the Wheel:
- The circumference [tex]\( C \)[/tex] of a circle (which the wheel is) is given by the formula:
[tex]\[ C = \pi \times d \][/tex]
where [tex]\( d \)[/tex] is the diameter.
3. Given:
- Diameter ([tex]\( d \)[/tex]) = 2 meters,
- Pi ([tex]\( \pi \)[/tex]) is approximately 3.1416.
4. Substitute the Values:
[tex]\[ C = \pi \times 2 \approx 3.1416 \times 2 = 6.2832 \text{ meters} \][/tex]
5. Calculate the Distance Traveled after 120 Rotations:
- If the wheel rotates 120 times, the total distance traveled [tex]\( D \)[/tex] can be found by multiplying the circumference of the wheel with the number of rotations.
[tex]\[ D = C \times \text{number of rotations} \][/tex]
[tex]\[ D = 6.2832 \times 120 = 753.984 \text{ meters} \][/tex]
6. Approximate the Answer:
- The closest option to 753.984 meters is 753.6 meters.
So, the correct answer is:
B. 753.6 meters