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the correct answer in each box. In a game at an amusement park, a player can win 20 points, 25 points, or 30 points. The probability of winning these points is given in the table. Points Probability 20 0.6 25 x 30 y If Jenny expects to win 22.5 points by playing the game once, the value of x is and the value of y is .



Answer :

lexie2fine

Answer:  We are given that the expected value of the game is 22.5 points. The expected value is the sum of the products of each outcome and its probability.

Let's set up the equation:

20(0.6) + 25(x) + 30(y) = 22.5

We know that the probabilities add up to 1, so we can write:

0.6 + x + y = 1

Now, we can solve for x and y.

First, let's solve for y:

y = 1 - 0.6 - x y = 0.4 - x

Now, substitute this expression for y into the first equation:

20(0.6) + 25(x) + 30(0.4 - x) = 22.5

Simplify the equation:

12 + 25x + 12 - 30x = 22.5

Combine like terms:

-5x = -1.5 x = 0.3

Now that we have the value of x, we can find the value of y:

y = 0.4 - x y = 0.4 - 0.3 y = 0.1

So, the correct answers are:

x = 0.3 y = 0.1

Step-by-step explanation: