Answered

8. What is the new pressure of 275 mL of a gas that is compressed to 175 mL, when the original pressure
was 4.0 atm
and the temperature is held constant?
a. 6.9 atm
b. 5.3 atm
c.
6,3 atm
d.
7.1 atm
e.
1.0 atm
the given molecular formula: C4H12



Answer :

To solve this problem, we will use Boyle's Law. Boyle's Law states that for a given mass of gas at constant temperature, the volume of the gas varies inversely with the pressure. Mathematically, it is expressed as:

[tex]\[ P_1 \times V_1 = P_2 \times V_2 \][/tex]

where:
- [tex]\( P_1 \)[/tex] is the initial pressure
- [tex]\( V_1 \)[/tex] is the initial volume
- [tex]\( P_2 \)[/tex] is the new (final) pressure
- [tex]\( V_2 \)[/tex] is the new (final) volume

Given the values:
- [tex]\( P_1 = 4.0 \text{ atm} \)[/tex]
- [tex]\( V_1 = 275 \text{ mL} \)[/tex]
- [tex]\( V_2 = 175 \text{ mL} \)[/tex]

We need to find [tex]\( P_2 \)[/tex]. Rearrange Boyle's Law to solve for [tex]\( P_2 \)[/tex]:

[tex]\[ P_2 = \frac{P_1 \times V_1}{V_2} \][/tex]

Substitute the known values into the equation:

[tex]\[ P_2 = \frac{4.0 \text{ atm} \times 275 \text{ mL}}{175 \text{ mL}} \][/tex]

Calculate the numerator:

[tex]\[ 4.0 \text{ atm} \times 275 \text{ mL} = 1100 \text{ atm·mL} \][/tex]

Now, divide by the new volume:

[tex]\[ P_2 = \frac{1100 \text{ atm·mL}}{175 \text{ mL}} \][/tex]

Perform the division:

[tex]\[ P_2 = 6.285714 \text{ atm} \][/tex]

We can round this value to one decimal place to match the options provided in the question:

[tex]\[ P_2 \approx 6.3 \text{ atm} \][/tex]

So, the new pressure when the gas is compressed to 175 mL is:

c. 6.3 atm