Answer:
[tex](3x+1)\text{ and }(x-1)[/tex]
Step-by-step explanation:
[tex]3x^3+7x^2-7x-3[/tex]
Since we know that [tex](x+3)[/tex] is one of the factors of this expression, let's split the terms so that each pair has [tex](x+3)[/tex] a common factor.
[tex]3x^3+7x^2-7x-3\\\\=3x^3+9x^2-2x^2-6x-x-3\\\\=3x^2(x+3)-2x(x+3)-1(x+3)\\\\=(x+3)(3x^2-2x-1)\\\\=(x+3)(3x^2-3x+x-1)\\\\=(x+3)\{3x(x-1)+1(x-1)\}\\\\=(x+3)(3x+1)(x-1)[/tex]
So, the other two factors are [tex](3x+1)[/tex] and [tex](x-1)[/tex].
