14. El segundo ángulo interno de un triángulo mide el doble de la medida del primer ángulo y una tercera
parte de la medida del tercer ángulo; ¿cuántos grados
mide cada uno de los tres ángulos internos?



Answer :

To solve this problem, let's denote the measures of the angles as follows:
- Let the first angle be x degrees.
- The second angle is then 2x degrees since it's double the measure of the first angle.
- The third angle would be (1/3)x degrees since it's a third of the third angle.

Now, we know that the sum of the interior angles of a triangle is always 180 degrees. So, we can set up an equation based on this information:

x + 2x + (1/3)x = 180

Combining like terms:
(6/3)x + (6/3)x + (2/3)x = 180
(9/3)x = 180
3x = 180
x = 60

Therefore, the angles measure:
- First angle: x = 60 degrees
- Second angle: 2x = 2(60) = 120 degrees
- Third angle: (1/3)x = (1/3)(60) = 20 degrees

Hence, the three angles of the triangle measure 60 degrees, 120 degrees, and 20 degrees, respectively.