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Normal Distribution - Find Z Score
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On a standardized exam, the scores are normally distributed with a mean of 400 and a standard
deviation of
20. Find the z-score of a person who scored 460 on the exam.
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Answer :

To find the z-score of a person who scored 460 on a standardized exam with a mean score of 400 and a standard deviation of 20, follow these steps:

### Step-by-Step Solution:

Step 1: Understand the z-score formula

The z-score is a measure that describes the position of a score within a distribution in terms of how many standard deviations it is away from the mean. The formula for the z-score is:

[tex]\[ z = \frac{X - \mu}{\sigma} \][/tex]

where:
- [tex]\( X \)[/tex] is the score for which we need to find the z-score.
- [tex]\( \mu \)[/tex] is the mean of the distribution.
- [tex]\( \sigma \)[/tex] is the standard deviation of the distribution.

Step 2: Identify the given values

From the problem, we know:
- The mean score ([tex]\( \mu \)[/tex]) is 400.
- The standard deviation ([tex]\( \sigma \)[/tex]) is 20.
- The score ([tex]\( X \)[/tex]) is 460.

Step 3: Substitute the values into the z-score formula

[tex]\[ z = \frac{460 - 400}{20} \][/tex]

Step 4: Simplify the expression

Perform the subtraction in the numerator:

[tex]\[ 460 - 400 = 60 \][/tex]

Now, divide the result by the standard deviation:

[tex]\[ z = \frac{60}{20} = 3 \][/tex]

Conclusion:

The z-score of a person who scored 460 on the exam is 3. This means that the person's score is 3 standard deviations above the mean score of the distribution.