5.
If a book with a weight of 30 N rests on a table, and the area of contact
between the book and the table is 0.1 m², what is the pressure exerted by
the book?



Answer :

To find the pressure exerted by the book on the table, we use the formula for pressure.

Pressure (P) is defined as the force (F) exerted per unit area (A):

[tex]\[ P = \frac{F}{A} \][/tex]

Given:
- The weight of the book (which acts as the force in this context) is [tex]\( F = 30 \)[/tex] Newtons.
- The area of contact between the book and the table is [tex]\( A = 0.1 \)[/tex] square meters.

Now, substitute the given values into the pressure formula:

[tex]\[ P = \frac{30 \, \text{N}}{0.1 \, \text{m}^2} \][/tex]

Perform the division:

[tex]\[ P = \frac{30}{0.1} \][/tex]

To divide by a fraction, you can multiply by the reciprocal of the fraction:

[tex]\[ P = 30 \times 10 \][/tex]

This results in:

[tex]\[ P = 300 \, \text{N/m}^2 \][/tex]

So, the pressure exerted by the book on the table is [tex]\( 300 \)[/tex] pascals (Pa), since 1 N/m² is equivalent to 1 Pascal (Pa).

Hence, the pressure exerted by the book is 300 Pa.