Triangle DEF has vertices at D(−3, 5), E(−10, 4), and F(−2, 2). Triangle D′E′F′ is the image of triangle DEF after a reflection. Determine the line of reflection if F′ is located at (−2, −2).

x = 2
y = 1
y-axis
x-axis



Answer :

Answer:

x-axis

Step-by-step explanation:

To determine the line of reflection that maps point \( F(-2, 2) \) to \( F'(-2, -2) \), let's analyze the coordinates of these points.

The reflection of a point across a line results in the point being equidistant from the line on the opposite side.

In this case, point \( F \) is at \( (-2, 2) \) and point \( F' \) is at \( (-2, -2) \).

1. **Reflecting Across a Horizontal Line**:

- The x-coordinates remain the same (both \(-2\)), so the line of reflection must be horizontal.

- The y-coordinates of \( F \) and \( F' \) are \( 2 \) and \(-2\), respectively. The midpoint of these y-coordinates is:

\[

\frac{2 + (-2)}{2} = 0

\]

- Thus, the horizontal line halfway between \( 2 \) and \(-2\) is the x-axis (or \( y = 0 \)).

Let's verify this:

- Reflecting \( F(-2, 2) \) over the x-axis ( \( y = 0 \) ):

- The x-coordinate remains the same: \(-2\).

- The y-coordinate changes to its opposite: \(-2\).

- This maps \( F(-2, 2) \) to \( F'(-2, -2) \).

Since this matches the given image \( F' \), the line of reflection is the **x-axis**.

So, the correct line of reflection is:

**x-axis**