Suppose you carry out a titration involving 0.22 molar HCl and an unknown concentration of LiOH. To bring the reaction to its end point, you add 12.3 milliliters of HCl to 18.0 milliliters of LiOH.

Now you know that you have a 0.15 M0.32 M1.0 M1.3 M solution of LiOH.

The volume of LiOH used is 18.0 mL. To find the concentration of LiOH, you can use the formula M1V1 = M2V2, where M1 is the molarity of the first solution, V1 is the volume of the first solution, M2 is the molarity of the second solution, and V2 is the volume of the second solution. Plugging in the values, you can calculate the concentration of LiOH.

Suppose you carry out a titration involving 0.22 molar HCl and an unknown concentration of LiOH. To bring the reaction to its end point, you add 12.3 milliliters of HCl to 18.0 milliliters of LiOH. Now you know that you have a 0.15 M0.32 M1.0 M1.3 M solution of LiOH.

Answer :

Other Questions

Suppose you carry out a titration involving 0.22 molar HCl and an unknown concentration of LiOH. To bring the reaction to its end point, you add 12.3 milliliters of HCl to 18.0 milliliters of LiOH.

Now you know that you have a 0.15 M0.32 M1.0 M1.3 M solution of LiOH.