Calculate the morality of a water solution ofbCaCl2 given that 5.04L of the solution contains 612g of CalCl2



Answer :

Answer:

1.094 M

1. Calculate the number of moles of CaCl₂

  The molar mass of CaCl₂ (calcium chloride) can be calculated by summing the atomic masses of calcium (Ca) and chlorine (Cl)

  - Calcium (Ca): 40.08 g/mol

  - Chlorine (Cl): 35.45 g/mol (since there are two chlorine atoms, multiply this by 2)

  Molar mass of CaCl₂ = 40.08 g/mol + (2 × 35.45 g/mol)

                     = 40.08 g/mol + 70.90 g/mol

                     = 110.98 g/mol

  Next, calculate the number of moles of CaCl₂: Number of moles = Mass/Molar mass

                         = 612g / 110.98 g/mol

                         = 5.515 moles

 2. Calculate the molarity of the solution

  Molarity (M) is defined as the number of moles of solute per liter of solution.

 Molarity = Number of moles / Volume of solution in liters

  Given:

  - Number of moles of CaCl₂ = 5.515 moles

  - Volume of solution = 5.04 L

  Molarity = 5.515  moles / 5.04 L

                  = 1.094 M

Therefore, the molarity of the CaCl₂ solution is approximately 1.094 M.