A 10 ft ladder leaning against a wall begins to slide. How fast is the top of the ladder sliding down the wall at the instant of time when the bottom of the ladder is 6ft from the wall and sliding away from the wall at the rate of 6ft/s?
Substituting y = 8 into dy/dt = -1.8/y, we find dy/dt = -1.8/8 = -0.225 ft/s. Therefore, when the foot of the ladder is 6 ft from the wall, the top of the ladder is sliding down the wall at a rate of approximately 0.225 ft/s.
