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Parmi les 160 élèves de Seconde d'un lycée, 47 ont lu
Bel Ami et 31 ont lu Germinal.
Au total 53 élèves ont lu au moins l'un des deux livres.
On tire au hasard la fiche d'un élève.
Déterminer la probabilité de l'événement:
E: «L'élève a lu les deux livres »;
F: «L'élève n'a lu aucun des deux livres ».



Answer :

GinnyAnswer

Final answer:

The answer provides calculations for the probability of an event where a student has read both books and the probability of a student having read none of the books among a group of 160 students.


Explanation:

Probability of Event E:

Number of students who read both books = Number who read Bel Ami + Number who read Germinal - Number who read both = 47 + 31 - 53 = 25.

Probability of Event E = Number of students who read both books / Total number of students = 25 / 160 = 0.15625.

Probability of Event F:

Number of students who read none = Total students - Number who read at least one book = 160 - 53 = 107.

Probability of Event F = Number of students who read none / Total number of students = 107 / 160 = 0.66875.

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