Blocks with masses of 3.0 kg, 4.0 kg, and 5.0 kg are lined up in a row on a frictionless table. All three are pushed forward by a 13 N force applied to the 3.0 kg block.How much force does the 4.0 kg block exert on the 3.0 kg block? Express your answer with the appropriate units.

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Smarty90 Smarty90 · Answer 1 · 2024-05-24T16:17:11-04:00

Answer:

First of all, i would recommend drawing a free-body diagram

then using that you can find the equations

as the force acting on the 3 kg block is 13 newtons and the normal reaction by the 3 kg block on the 4 kg block

and the reverse force will be the normal reaction of a 4 kg block on a 3kg block

so you get the equation as F +N = -N

remember to consider directions as force is a vector quantity

which gives F = -2N

you get negative force due to the face that the force exerted by 4 kg on 3kg is opposite right

so you get the N = 13/2 = 6.5N

HEnce the Answer is 6.5N