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A principal of $3000 is Invested at 7.75% Interest, compounded annually. How much will the Investment be worth after 14 years?
Use the calculator provided and round your answer to the nearest dollar.
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Answer :

Certainly! To find out how much an investment of [tex]$3000 at an annual interest rate of 7.75%, compounded annually, will be worth after 14 years, we use the compound interest formula. Here is the step-by-step solution: The compound interest formula is: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount (initial investment). - \( r \) is the annual interest rate (decimal). - \( n \) is the number of times that interest is compounded per year. - \( t \) is the time the money is invested for in years. In this problem: - \( P = 3000 \) dollars - \( r = 7.75\% = 0.0775 \) (convert percentage to decimal) - Since the interest is compounded annually, \( n = 1 \) - \( t = 14 \) years Given that the interest is compounded annually, the formula simplifies to: \[ A = P \left(1 + r\right)^t \] Now we substitute the given values into the formula: \[ A = 3000 \left(1 + 0.0775\right)^{14} \] Calculate the term inside the parentheses first: \[ 1 + 0.0775 = 1.0775 \] Raise this value to the power of 14: \[ 1.0775^{14} \approx 2.9527 \] Multiply by the principal amount: \[ A = 3000 \times 2.9527 \approx 8858.1 \] Finally, round the result to the nearest dollar: \[ A \approx 8858 \] So, the investment will be worth approximately $[/tex]8,858 after 14 years.
Well because your principle is 3000, and you compound interest formula is A=P(1+r/n)^nt you will plug in 3000 for P. And your rate 7.75% also .0775 will replace R.

So A=3000(1+.0775/12)^12 x 14.

A=3000(1.006)^168
A=3000(2.53)
A= 7590

So your answer would be estimated to 7590.

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