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A Computer Science lecturer gave his class two tests. 25% of the class passed both tests and 42% of the class passed the first test. What percent of those who passed the second test also passed the first test? [3]



Answer :

rvkacademic

Answer:

59.52%

Step-by-step explanation:

  • Let us assume that there were a total of 100 students in the class. Then we get to work with whole numbers instead of percentages or fraction
  • Out of 100 students, 25% passed the both tests means
    25% x 100 = 25 students passed both tests
  • 42% passed first test => 42 students passed the first test
  • The problem asks what percent is 25 of 42.
    = 25/42 * 100 = 59.52%

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