A sailor pulls a boat 15.0 m along a dock using a rope that makes a 45.0° angle with the horizontal. How much work does the sailor do on the boat if he exerts a force of 185 N on the rope?



Answer :

Answer:

The work is defined by the product of force and displacement. Its standard formula is,

W = F.d.Cos\alpha

Here F is force, d is displacement and α is angle subtended by force from horizontal.

As given in the question,

F = 255N, d = 30m, α = 30°

On putting in the above formula

W = 255×30×Cos30°

=7650×0.906

= 6930.9 J

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Answer: 6117.58 J

Explanation:

We know that W=Fd*cos(theta) where theta is the angle between the displacement and the force.

In this case, we are given that F=225 N, d=30 m, and theta=25 degrees.

Plugging all this in we get

W=225*30*cos(25)=6117.58 J

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Verified answer

a sailor pulls a boat 30.0 m along a dock using a rope that makes 25.0 angle with the horizontal. how much work does the sailor do on the obat if he exerts a force of 255 n on the rope?

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