victorlin0 victorlin0
  • 26-05-2024
  • Mathematics
Answered

Solve for x.
sqrt[(2x^2)+1]=a
a>1



Answer :

ismaildarouich702 ismaildarouich702
  • 26-05-2024

Answer:

Step-by-step explanation:Solving for x in the equation sqrt(2x^2+1)=0:Rewrite the equation as √(2x^2 + 1) = 0Square both sides to get 2x^2 + 1 = 0Solve for x to find the solutionrationalise by multiply sqrt2/sqrt2 hence we got   as final answer.

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