Answer :
Solution
As we have
SinA = 6/10=p/h
perpendicular (p) =6
hypotenuse (h)= 10
By pythagoras theorem
h^2=p^2+b^2
b= 8
Now,
Cos A = b/h = 8/10
tanA = P/b = 6/8
cosecA = h/p = 10/6
secA = h/b= 6/8
cotA = b/p = 8/6
Solution
As we have
SinA = 6/10=p/h
perpendicular (p) =6
hypotenuse (h)= 10
By pythagoras theorem
h^2=p^2+b^2
b= 8
Now,
Cos A = b/h = 8/10
tanA = P/b = 6/8
cosecA = h/p = 10/6
secA = h/b= 6/8
cotA = b/p = 8/6