A machine which manufactures ice needs to be run for 10 minutes to warm up before the production of ice begins. The mass, in tones, of ice produced is directly proportional to the number of hours of production. Given that 20 tones of ice are produced when the machine runs for half an hour, find the mass of ice manufactured when the machine runs for 1.75 hours.



Answer :

Answer:

95

Step-by-step explanation:

According to given information, machine runs

half an hours to produce 20 tones of ice, and it is also mention that

machine need to run 10 mins to warm up.

half an hours means = 30 mins

total time machine runs is = 30 -10= 20 mins

10 mins is warm up time

So, in 20 mins it produces 20 tones of ice.
And we have to find how much ice in produced if machine runs for 1.75 hours.

Let convert hours to mins

1.75 hours x 60 = 105 mins

We know, 10 mins need for warm up, so actually the machine rans for

105 mins - 10 mins = 95 mins

Now, we have to see weather its a directly proportional or inverse proportional

Ice tones         machine time

20                        20 mins

x                           95 mins

( In 20 mins , machine produce 20 tones of ice, so in 95 mins it produce greater than 20 tones of ice. Direct proportion said that, when one thing is increasing the other thing is also increasing.)

Mathematically,

[tex]\frac{20}{x}=\frac{20}{95}\\[/tex]

x= [tex]\frac{20. 95}{20}[/tex]

x = 95 tones

Result:

When machine runs for 1.75 hours it produces 95 tones of ice.