6. A triangle has one angle that measures five degrees more than twice the smallest angle. Also, the largest angle
measures eleven degrees less than three times the measure of the smallest angle. Find the measures of all three
angles.



Answer :

To find the measures of all three angles in a triangle given the conditions, we can proceed with the following steps:

1. Assign Variables:
- Let the smallest angle be denoted as [tex]\( x \)[/tex] degrees.

2. Express the Other Angles:
- According to the problem, one angle measures five degrees more than twice the smallest angle. This angle can be written as:
[tex]\[ 2x + 5 \][/tex]
- The largest angle measures eleven degrees less than three times the measure of the smallest angle. This angle can be written as:
[tex]\[ 3x - 11 \][/tex]

3. Set Up the Triangle Angle Sum Equation:
- The sum of the angles in any triangle is always 180 degrees. Hence, we can set up the equation:
[tex]\[ x + (2x + 5) + (3x - 11) = 180 \][/tex]

4. Combine Like Terms and Solve for [tex]\( x \)[/tex]:
[tex]\[ x + 2x + 5 + 3x - 11 = 180 \][/tex]
[tex]\[ 6x - 6 = 180 \][/tex]
[tex]\[ 6x = 186 \][/tex]
[tex]\[ x = 31 \][/tex]

5. Find the Measures of All Angles:
- The smallest angle [tex]\( x \)[/tex] is:
[tex]\[ x = 31 \text{ degrees} \][/tex]
- The second angle [tex]\( (2x + 5) \)[/tex] is:
[tex]\[ 2(31) + 5 = 62 + 5 = 67 \text{ degrees} \][/tex]
- The largest angle [tex]\( (3x - 11) \)[/tex] is:
[tex]\[ 3(31) - 11 = 93 - 11 = 82 \text{ degrees} \][/tex]

6. Verify the Sum of the Angles:
- Sum of the angles:
[tex]\[ 31 + 67 + 82 = 180 \text{ degrees} \][/tex]
- This confirms that the angles add up to 180 degrees as required for a triangle.

So, the measures of the three angles in the triangle are:
- 31 degrees (smallest angle)
- 67 degrees (second angle)
- 82 degrees (largest angle)

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