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The combustion of Octane (gasoline) is this balanced chemical equation. 2C8H18 25O2 -> 18H2O 16CO2 How many atoms of oxygen are in the reactants and products of this equation? Question 5 options: 50 in the reactants and 50 in the products 25 in the reactants and 34 in the products 25 in the reactants and 18 in the products 25 in the reactants 25 in the reactants and 16 in the products.



Answer :

nidaaslam1013

In the given balanced chemical equation for the combustion of Ocatane: Reactants: -Total number of oxygen atoms in the reactants = 50 Products: Total number of oxygen atoms in the products:50 Therefore, the number of oxygen atoms in the reactants and the product of the equation is 50 each.

This answer explains the number of oxygen atoms in the reactants and products of the combustion of octane using a balanced chemical equation.

The reactants: 2(C8H18) + 25(O2) = 2(8*8 + 18*1) + 25*2 = 16 carbon atoms, 36 hydrogen atoms, and 50 oxygen atoms.

The products: 16(CO2) + 18(H2O) = 16*1*2 + 18*1*2 = 16 carbon atoms, 36 hydrogen atoms, and 50 oxygen atoms.

Therefore, there are 25 atoms of oxygen in both the reactants and products.