Answer :
- The electron configuration of Al atom is 1s²2s²2p63s²3p¹.
- Aluminum has three valence electrons in the third energy level (3s²3p¹).
- Aluminum loses three electrons to form Al³+, which then has the electron configuration of the noble gas neon, 1s²2s²2p6 in its outermost shell.
- Therefore, Al³+ has 0 electrons in its outermost shell.
The electronic configuration of Al³+ is 1s² 2s² 2p⁶. It has 10 electrons in total, with 8 electrons in its outermost shell.
The electronic configuration of a neutral aluminum (Al) atom with atomic number 13 is: 1s² 2s² 2p⁶ 3s² 3p¹. Aluminum has three valence electrons in the 3s and 3p orbitals (3s² 3p¹).
To form the Al³⁺ ion, aluminum loses its three valence electrons. The resulting electronic configuration for Al³⁺ is: 1s² 2s² 2p⁶, which is the same as the electron configuration of the noble gas neon.
Electrons in the Outermost Shell
In the Al³⁺ ion, the outermost shell (n = 2) has 8 electrons, all of which are in the 2s and 2p orbitals.
Summary: The Al³⁺ ion has 10 electrons, and there are 8 electrons in its outermost shell after losing three valence electrons.
