Answer :
To solve the quadratic equation -x²+3x-5=0 by completing the square, rearrange the equation, complete the square, factor the perfect square trinomial, and then solve for x.
Quadratic equation: -x²+3x-5=0
To solve by completing the square:
- Rearrange the equation to have x-terms on one side: x² - 3x = 5
- Complete the square by adding (3/2)² to both sides: x² - 3x + (3/2)² = 5 + (3/2)²
- Factor the perfect square trinomial: (x - 3/2)² = 5 + 9/4
- Solve for x
- final answer for this expression x = 3/2 ± √(5 + 9/4)
To solve the quadratic equation -x^2 + 3x - 5 = 0 by completing the square, first, rearrange it to make the coefficient of x^2 positive, then complete the square to derive the solutions in terms of complex numbers.
Explanation:
A student has asked the following question:
Solve the following quadratic equation by completing the square: -[tex]x^{2}[/tex] + 3x - 5 = 0
To solve the quadratic equation by completing the square, we can follow these steps:
First, rearrange the equation into the standard form, making the coefficient of x2 positive:
[tex]x^{2} -3x+5=0[/tex]
Next, move the constant term to the right side of the equation:
[tex]x^{2} -3x=-5[/tex]
To complete the square, add and subtract (b/2)2 to the left side. Here, b is -3, so (b/2)2 = (3/2)2:
[tex]x^{2} -3x+(\frac{3}{2})^{2} = -5+(\frac{3}{2})^{2}[/tex]
Simplify the equation:
[tex]x^{2} -3x+\frac{9}{4}= -\frac{20}{4}+\frac{9}{4}[/tex]
Combine the terms on the right side:
[tex]x^{2} -3x+\frac{9}{4}= -\frac{11}{4}[/tex]
Now, write the left-hand side as a perfect square:
[tex](x-\frac{3}{2})^{2}= -\frac{11}{4}[/tex]
Take the square root of both sides, being mindful of the plus-minus sign:
[tex]x-\frac{3}{2}= \pm\sqrt{-\frac{11}{4}}[/tex]
[tex]x-\frac{3}{2}= \pm(i\frac{\sqrt{11}}{2} )[/tex]
where [tex]i[/tex] is the imaginary unit.
Finally, solve for x:
[tex]x=\frac{3}{2} \pm(\frac{\sqrt{11}}{2} )i[/tex]
This shows the solutions in terms of complex numbers i.e. [tex]x=\frac{3}{2} + (\frac{\sqrt{11}}{2} )i \ \ \& \ \ x=\frac{3}{2} -(\frac{\sqrt{11}}{2} )i[/tex]