A chemist wishes to make 30 Liters of a 45% alcohol solution by mixing a 35% alcohol solution and a 60% alcohol solution. How much of each type of solution should he use?
Your equation should only have one variable! ONLY answer with equation.



Answer :

18 liters of the 35% solution and 12 liters of the 60% solution

======================

Let x be the volume of the 35% solution and (30 - x) be the volume of the 60% solution.

Set up the equation for the amount of alcohol concentration:

  • 0.35x + 0.60(30 - x) = 0.45(30)

Calculate the amount of 35% solution by solving the equation:

  • 0.35x + 0.60(30 - x) = 0.45(30)
  • 0.35x + 18 - 0.6x = 13.5
  • 0.6x - 0.35x = 18 - 13.5
  • 0.25x = 4.5
  • x = 4.5/0.25
  • x = 18

Find the amount of 60% solution:

  • 30 - 18 = 12 liters