Answer:
To determine the coordinates of the points \((x, 2.7)\) that lie on the circle defined by the equation \(x^2 + y^2 = 16\), we need to substitute \(y = 2.7\) into the equation and solve for \(x\).
Given:
\[ x^2 + y^2 = 16 \]
Substitute \(y = 2.7\):
\[ x^2 + (2.7)^2 = 16 \]
Calculate \(2.7^2\):
\[ 2.7^2 = 7.29 \]
Thus, the equation becomes:
\[ x^2 + 7.29 = 16 \]
Subtract 7.29 from both sides:
\[ x^2 = 16 - 7.29 \]
\[ x^2 = 8.71 \]
Solve for \(x\):
\[ x = \pm \sqrt{8.71} \]
So the two points \((x, 2.7)\) on the circle are:
\[ (\sqrt{8.71}, 2.7) \text{ and } (-\sqrt{8.71}, 2.7) \]
Hence, the points are:
\[ \left( \sqrt{8.71}, 2.7 \right), \left( -\sqrt{8.71}, 2.7 \right) \]
Step-by-step explanation:
