Answer:
13.6 N
Explanation:
Using the provided free-body diagram, we can apply Newton's second law of motion to balance the forces on each mass. Since no coefficient of friction is given, we will assume the plane is frictionless. If we assume the pulley is also frictionless, then the tension forces are equal, so T₁ = T₂ = T. In the diagram:
- C is the weight of M₁, C = M₁g. This weight force has components parallel to the plane (A) and perpendicular to the plane (B)
- D is the normal force, D = N
- E is the weight of M₂, E = M₂g
Summing the forces on M₂ in the vertical direction:
∑F = ma
T − M₂g = 0
T = M₂g
Summing the forces on M₁ in the parallel direction (use trigonometry to show that A = M₁g sin θ):
T − M₁g sin θ = 0
T = M₁g sin θ
Setting the equations equal:
M₂g = M₁g sin θ
Plug in values:
M₂g = 25.0 N sin 33.0°
M₂g = 13.6 N
