8. The 600 N ball shown is suspended on a string AB and rests against a frictionless vertical wall.
The string makes an angle of 30° with the wall. The magnitude of the tension force of the string is:
(a) 400 √√3 N (b) 1200 N (c) 400 √2 N
(d) 2400 N

By drawing a free body diagram, which is a diagram of all the forces acting on the ball, we can balance the forces and solve for the tension. There are three forces on the ball:

Weight force mg pulling down
Tension force T pulling up 30° from the vertical
Normal force N pushing horizontally

Summing the forces in the vertical direction:

∑F = ma

T cos 30° − mg = 0

T cos 30° = mg

T = mg / cos 30°

Plug in values:

T = (600 N) / cos 30°

T = (600 N) / (√3 / 2)

T = 1200 N / √3

T = 400√3 N

8. The 600 N ball shown is suspended on a string AB and rests against a frictionless vertical wall.The string makes an angle of 30° with the wall. The magnitude of the tension force of the string is:(a) 400 √√3 N (b) 1200 N (c) 400 √2 N(d) 2400 N​

Answer :

Other Questions

8. The 600 N ball shown is suspended on a string AB and rests against a frictionless vertical wall.
The string makes an angle of 30° with the wall. The magnitude of the tension force of the string is:
(a) 400 √√3 N (b) 1200 N (c) 400 √2 N
(d) 2400 N