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7. A 2600-pound truck is stopped at a red light on a hill with an incline of 25°. Ignoring the force of friction, what force is required to keep the truck from rolling down the hill?
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Answer :

Answer:

Well draw with a diagram what it says it would be a triangle with an incline of 25 degrees with a truck sliding

so the only force acting backward will be then the brake force as friction is ignored so that force would equal mg sinx as that is the only force acting back and the normal reaction would equal mg cos x for the truck to be in equilibrium

2600 pound = 1120 KG

so the force would be mg sin25 = 1120 kg * 9.81 * sin 25 = 4643Newton of force by the brakes or any other resisting force

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