reserved.
carbonate
CO₂²-
ammonium
hypocarbonite
CO2-
cyanide
hydrogen carbonate
(bicarbonate)
HCO3
hydroxide
chlorite
CIO-
peroxide
What is the mass of 1.72 moles of sodium nitrate? Use the periodic table and the polyatomic ion resource.
O A.
85.0 g
O B.
91.2 g
O C. 146 g
O D.
273 g
E
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Answer :

To determine the mass of 1.72 moles of sodium nitrate (NaNO₃), we need to follow a few steps involving the calculation of the molar mass of sodium nitrate and then the multiplication by the number of moles given. Let's break it down step-by-step.

### Step 1: Determine the Molar Mass of Sodium Nitrate (NaNO₃)

1. Identify the Atomic Masses from the Periodic Table:
- Sodium (Na): 22.99 g/mol
- Nitrogen (N): 14.01 g/mol
- Oxygen (O): 16.00 g/mol

2. Determine the Number of Each Atom in the Compound:
- Sodium nitrate (NaNO₃) consists of 1 sodium (Na), 1 nitrogen (N), and 3 oxygen (O) atoms.

3. Calculate the Molar Mass of Each Element in the Compound:
- Molar mass of Na: [tex]\( 1 \times 22.99 \)[/tex] g/mol = 22.99 g/mol
- Molar mass of N: [tex]\( 1 \times 14.01 \)[/tex] g/mol = 14.01 g/mol
- Molar mass of O: [tex]\( 3 \times 16.00 \)[/tex] g/mol = 48.00 g/mol

4. Sum the Molar Masses to Get the Total Molar Mass of Sodium Nitrate:
[tex]\[ \text{Molar mass of NaNO₃} = 22.99 \, \text{g/mol} + 14.01 \, \text{g/mol} + 48.00 \, \text{g/mol} = 85.00 \, \text{g/mol} \][/tex]

### Step 2: Calculate the Mass of 1.72 Moles of Sodium Nitrate

Given that:
- The molar mass (MM) of NaNO₃ is 85.00 g/mol
- The number of moles (n) of NaNO₃ is 1.72

1. Use the Formula:
[tex]\[ \text{Mass} = \text{Molar mass} \times \text{Number of moles} \][/tex]

2. Substitute the Given Values:
[tex]\[ \text{Mass} = 85.00 \, \text{g/mol} \times 1.72 \, \text{mol} \][/tex]

3. Calculate the Mass:
[tex]\[ \text{Mass} = 146.2 \, \text{g} \][/tex]

Thus, the mass of 1.72 moles of sodium nitrate (NaNO₃) is [tex]\( 146.2 \)[/tex] grams.

The correct answer is:
- Option C: 146 g.