A 2 kg block has an initial velocity of 5.00 m/s as it starts sliding up a 30º inclined plane. How far up the inclined plane does the block slide before it stops? Label your answer.



Answer :

Answer:

2.55 m

Explanation:

The energy of the block is conserved. The block's initial kinetic energy (KE) is converted to gravitational potential energy (PE). The kinetic energy is equal to half the mass (m) times the square of the speed (v), and the potential energy is equal to the weight (mg) times the height (h). Once we find the height, we can use trigonometry to find the distance along the plane.

KE = PE

½ mv² = mgh

½ v² = gh

h = ½ v² / g

h = ½ (5.00 m/s)² / (9.8 m/s²)

h = 1.28 m

Using trigonometry:

sin θ = h / L

sin 30° = 1.28 m / L

L = 2.55 m