A portion on rim of a wheel having circumference 24m covers a horizontal distance on the road 10m.What is the angular displacement of the point



Answer :

Answer:

5π/6 radians

Explanation:

The horizontal distance traveled along the road is equal to the arc length (s) of the path traveled by the point. Knowing that the circumference (C) of the circle corresponds to 2π radians, we can write a proportion to solve for the angular displacement (θ) of the point.

[tex]\huge \text {$ \frac{s}{c} $} \Large \text {$\ =\ $} \huge \text {$ \frac{\theta}{2\pi} $}\\\\\huge \text {$ \frac{10\ m}{24\ m} $}\Large \text {$\ =\ $} \huge \text {$ \frac{\theta}{2\pi} $}\\\\\huge \text {$ \frac{20\pi}{24} $}\Large \text {$\ = \theta$}\\\Large \text {$ \theta = $}\huge \text {$ \frac{5\pi}{6} $}[/tex]

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