Grade 5: MRL CC 2022 Chapter 6 Practice Test Question 9
A division problem has 47 as its divisor. The partial quotients are 20 and 6. The remainder is 13. What
is the dividend?
The dividend is



Answer :

To solve this problem, we need to find the dividend given the divisor, partial quotients, and the remainder. Here are the steps:

1. Understand the Problem:
- Divisor: 47
- Partial Quotients: 20 and 6
- Remainder: 13

2. Calculate the Total Quotient:
The total quotient is the sum of the partial quotients.
[tex]\[ \text{Total Quotient} = 20 + 6 = 26 \][/tex]

3. Use the Relationship Between Dividend, Divisor, Quotient, and Remainder:
The formula to find the dividend is:
[tex]\[ \text{Dividend} = (\text{Total Quotient} \times \text{Divisor}) + \text{Remainder} \][/tex]

4. Plug in the Values:
- Total Quotient: 26
- Divisor: 47
- Remainder: 13
[tex]\[ \text{Dividend} = (26 \times 47) + 13 \][/tex]

5. Calculate the Product and Sum:
- First, calculate the product:
[tex]\[ 26 \times 47 = 1222 \][/tex]
- Then, add the remainder:
[tex]\[ 1222 + 13 = 1235 \][/tex]

So, the dividend is [tex]\( 1235 \)[/tex].

Thus, the dividend is [tex]\( 1235 \)[/tex].