A stone is thrown upward at a speed of 52 ft/s from the edge of a cliff that is 378 ft above the ground. Find the stones height above the ground, h(t), after t seconds.



Answer :

Step-by-step explanation:

To find the height of the stone above the ground, h(t), after t seconds, we can use the equation h(t) = -16t^2 + vt + h0, where:

- h(t) is the height of the stone (in feet) at time t,

- v is the initial velocity of the stone (in feet per second), and

- h0 is the initial height of the stone (in feet).

Given:

- Initial velocity, v = 52 ft/s (upward),

- Initial height, h0 = 378 ft.

Plugging in the values, we get:

h(t) = -16t^2 + 52t + 378

So, the height of the stone above the ground after t seconds can be calculated using the above equation.