Daniel bought a bag of 32 candy-coated chocolates. Of those candies, 11 are blue and 10 are
orange. If Daniel selects a candy at random, what is the probability that the candy will NOT be
blue orange?
a) 21/32
c) 11/16
b) 1/2
d) 11/32



Answer :

To determine the probability that a randomly selected candy from Daniel's bag will NOT be blue or orange, we can follow these steps:

1. Total Number of Candies:
- Daniel has a total of 32 candy-coated chocolates.

2. Count of Blue Candies:
- There are 11 blue candies in the bag.

3. Count of Orange Candies:
- There are 10 orange candies in the bag.

4. Count of Blue or Orange Candies:
- To find the total number of candies that are either blue or orange, we add the blue candies and orange candies together.
- Blue candies + Orange candies = 11 + 10 = 21

5. Count of Candies that are Neither Blue nor Orange:
- To find the number of candies that are neither blue nor orange, we subtract the number of blue or orange candies from the total number of candies.
- Total candies - Blue or Orange candies = 32 - 21 = 11

6. Determine the Probability:
- The probability of selecting a candy that is NOT blue or orange is the ratio of the number of candies that are neither blue nor orange to the total number of candies.
- Probability = (Number of candies that are neither blue nor orange) / (Total number of candies)
- Probability = 11 / 32

Thus, the probability that the candy Daniel selects is NOT blue or orange is [tex]\(\frac{11}{32}\)[/tex].

The correct option is:
d) [tex]\(\frac{11}{32}\)[/tex]