Answer :
To determine the resistance of an automobile headlight given that a current of 2.50 amperes (A) flows through it when a voltage of 12.0 volts (V) is applied, we can use Ohm's Law. Ohm's Law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and its resistance (R). This can be formulated as:
[tex]\[ V = I \times R \][/tex]
To solve for resistance (R), we rearrange the formula:
[tex]\[ R = \frac{V}{I} \][/tex]
Let's plug in the given values:
- Voltage, [tex]\( V = 12.0 \)[/tex] volts
- Current, [tex]\( I = 2.50 \)[/tex] amperes
Now, substitute these values into the rearranged formula:
[tex]\[ R = \frac{12.0 \text{ V}}{2.50 \text{ A}} \][/tex]
Carrying out the division:
[tex]\[ R = 4.8 \text{ ohms} \][/tex]
Therefore, the resistance of the automobile headlight is [tex]\( 4.8 \)[/tex] ohms.
[tex]\[ V = I \times R \][/tex]
To solve for resistance (R), we rearrange the formula:
[tex]\[ R = \frac{V}{I} \][/tex]
Let's plug in the given values:
- Voltage, [tex]\( V = 12.0 \)[/tex] volts
- Current, [tex]\( I = 2.50 \)[/tex] amperes
Now, substitute these values into the rearranged formula:
[tex]\[ R = \frac{12.0 \text{ V}}{2.50 \text{ A}} \][/tex]
Carrying out the division:
[tex]\[ R = 4.8 \text{ ohms} \][/tex]
Therefore, the resistance of the automobile headlight is [tex]\( 4.8 \)[/tex] ohms.