Step-by-step explanation:
Let's address each part of the problem:
**C. Find the radius of the cylinder:**
The formula for the cross-sectional area (\(A\)) of a cylinder is given by:
[tex]\[ A = \pi r^2 \][/tex]
Given that the cross-sectional area \(A\) is \(40 \, \text{cm}^2\) and the height \(h\) is \(5 \, \text{cm}\), we can rearrange the formula to solve for the radius \(r\):
[tex]\[ 40 = \pi r^2 \][/tex]
[tex]\[ r^2 = \frac{40}{\pi} \][/tex]
[tex]\[ r = \sqrt{\frac{40}{\pi}} \][/tex]
[tex]\[ r \approx 3.183 \, \text{cm} \][/tex]
So, the radius of the cylinder is approximately
[tex]\(3.183 \, \text{cm}\).[/tex]
**B. Find the length of side BD:**
Without a diagram or further context, it's challenging to determine side BD. Could you provide more information or clarify the context?
**14. Find the area of the wheel:**
To find the area of the wheel, we need to know the formula for the area of a circle, which is:
[tex]\[ A = \pi r^2 \][/tex]
Given that the radius
[tex]\(r\) is \(6 \, \text{[/tex]
One Question From Me
Q- Where Are You From ?
Answer in Comment
I am from India