Answered

Suppose you need to find information from a table
of values. You want a formula that does all of the
following:
•
Looks for a value from C1 in column E and
returns the value from column F, but only if
C1 is less than 5.
You want a precise match of C1 to the value
in column E.
If C1 is not less than 5, then take C1 and
multiply it by 2.
If there is an error, display "No relevant value
found".
Which formula would meet all of these criteria?



Answer :

GinnyAnswer
Sure, let's work through the problem step-by-step:

1. Check if C1 is less than 5: If C1 is indeed less than 5, we will proceed to look for a precise match in column E.

2. Look for a precise match in column E: If a match is found, return the corresponding value in column F. If no match is found, display "No relevant value found".

3. If C1 is not less than 5, multiply it by 2.

Now let me break down each case given an example setup:

### Example Values:
- C1 = 4
- Column E: [3, 4, 5, 6]
- Column F: ['a', 'b', 'c', 'd']

### Steps:
1. Is C1 less than 5?
- Yes, C1 = 4 is less than 5.

2. Check if C1 (which is 4) matches any value in column E:
- Column E contains [3, 4, 5, 6], and 4 is one of these values.
- Find the index of 4 in column E, which is index 1.

3. Return the corresponding value from column F:
- The value at index 1 in column F is 'b'.

Since C1 is less than 5 and a match is found, the value returned is 'b'.

By following the logic:

- If C1 was not less than 5, for instance if C1 = 6, the formula would multiply it by 2, giving a result of 12.

- If no match had been found in column E when C1 < 5, the result would have been "No relevant value found".

For the given scenario, the correct result derived from the calculation is 'b'. This ensures that all specified conditions and potential errors are accounted for properly.

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