Answer:
See attachment.
Step-by-step explanation:
The given linear equation, y = 4x - 9, is in slope-intercept form:
[tex]\boxed{\begin{array}{l}\underline{\textsf{Slope-intercept form of a linear equation}}\\\\y=mx+b\\\\\textsf{where:}\\\phantom{ww}\bullet\;\;\textsf{$m$ is the slope.}\\\phantom{ww}\bullet\;\;\textsf{$b$ is the $y$-intercept.}\\\end{array}}[/tex]
Therefore, in this case:
- The slope (m) is 4.
- The y-intercept (b) is -9.
To graph the linear equation y = 4x - 9, begin by plotting the y-intercept at point (0, -9).
If the slope of a line is 4, it means that for every 1 unit increase in the positive x-direction, the y-value increases by 4 units. Therefore, given any point on the line, we can find another point by adding 1 to the x-coordinate and adding 4 to the y-coordinate. So, another point on the line would be:
(0 + 1, -9 + 4) = (1, -5)
Plot the point (1, -5) and draw a straight line that passes through this point and the y-intercept at (0, -9).
