A water tank has the shape of a horizontal cylinder with radius 1 and length 2. If water is being pumped into the tank at a rate of m3 per minute, find the rate at which the water level is rising when the water is m deep.



Answer :

To find the rate at which the water level is rising, we can use the formula for the volume of a cylinder: V = πr^2h, where r is the radius and h is the height of the water.

Given that the radius is 1 and the length is 2, the volume V = π(1)^2(2) = 2π.

Since water is being pumped in at a rate of m^3 per minute, the rate of change of volume with respect to time is dm/dt = m.

To find the rate at which the water level is rising when the water is m deep, we can differentiate the volume formula with respect to time t: dV/dt = πr^2 dh/dt.

Substitute the known values:
2π = π(1)^2 dh/dt,
2 = dh/dt.

Therefore, the rate at which the water level is rising when the water is m deep is 2 units per minute.