Task: How can I factor this?
So far, you have mostly been working with expressions that are in the standard form ax² + bx + c. That is, the
terms are all positive. But, what
happens if a term is negative? Explore how to use algebra tiles to factor these
non-standard expressions by following the tutorials below.
3. [10 points] Factor x² - 3x + 2 with algebra tiles by:
a. Building and sketching a rectangular figure representing the expression.
b. Identifying the side lengths of the rectangle. Although it may sound counterintuitive, or
opposite of what you first think, label the lengths that are represented by
a negative
tiles as
1 or x.
-
c. Writing an equation showing that the area is equal to the product of is side length factors.
Check by multiplying the factors to get the original expression.
4. [10 points] Sometimes zero pairs must be added to close the rectangle. Adding zero pairs does not
change the value of the original expression since they, like their name implies, equate to 0. For
example, if you need to add an x tile, you MUST also add a - x tile to keep the balance of the
expression. Factor 2x² + x - 6 with algebra tiles by:
a. Building and sketching a rectangular figure representing the expression. Indicate the zero
pairs you added to close the rectangle.
b. Identifying the side lengths of the rectangle. Remember to use negative lengths appropriately.
c. Writing an equation showing that the area is equal to the product of its side length factors.
Check by multiplying the factors to get the original expression.



Answer :

Sure! Let's go through the steps to factor the given quadratic expressions using algebra tiles and then verifying the factors.

### Step 1: Factor [tex]\( x^2 - 3x + 2 \)[/tex]

#### a. Building and Sketching a Rectangular Figure
1. Represent [tex]\( x^2 \)[/tex]: First, we have a single [tex]\( x^2 \)[/tex] tile.
2. Represent [tex]\( -3x \)[/tex]: Next, we have 3 negative [tex]\( x \)[/tex] tiles.
3. Represent +2: Finally, we have 2 positive unit tiles.

To factor the expression, we arrange these tiles in a rectangular shape:
- Place the [tex]\( x^2 \)[/tex] tile in the top-left corner.
- Arrange -3x tiles in such a way to form the sides of a rectangle.
- The positive unit tiles will fit in the remaining spaces to complete the rectangle.

This setup should help us identify the length and width of the rectangle formed by the algebra tiles.

#### b. Identifying the Side Lengths
By arranging the tiles correctly:

- The [tex]\( x^2 \)[/tex] tile suggests the dimensions start with [tex]\( x \)[/tex].
- The factors [tex]\( (x-2) \)[/tex] and [tex]\( (x-1) \)[/tex] complete the rectangle since:
- The length [tex]\( x - 1 \)[/tex] represents 1 [tex]\( x \)[/tex] tile and 1 unit tile.
- The width [tex]\( x - 2 \)[/tex] represents 1 [tex]\( x \)[/tex] tile and 2 unit tiles.

#### c. Writing an Equation
We have:
[tex]\[ (x - 2) \times (x - 1) = x^2 - 3x + 2 \][/tex]

### Step 2: Factor [tex]\( 2x^2 + x - 6 \)[/tex]

#### a. Building and Sketching a Rectangular Figure
1. Represent [tex]\( 2x^2 \)[/tex]: We need 2 [tex]\( x^2 \)[/tex] tiles.
2. Represent [tex]\( x \)[/tex]: We need 1 positive [tex]\( x \)[/tex] tile.
3. Represent [tex]\( -6 \)[/tex]: We need 6 negative unit tiles.

We might need to add zero pairs (an [tex]\( x \)[/tex] tile and a [tex]\( -x \)[/tex] tile) to form a complete rectangle.

#### b. Identifying the Side Lengths
Arrange the tiles to form a rectangle:
- Place [tex]\( 2x^2 \)[/tex] tiles to start with.
- Arrange the remaining [tex]\( x \)[/tex] tile and [tex]\(-6\)[/tex] unit tiles around these.
- Zero pairs help fill any gaps.

The correct arrangement will help us identify the factors [tex]\( (x + 2) \)[/tex] and [tex]\( (2x - 3) \)[/tex]:
- The length [tex]\( 2x - 3 \)[/tex]: Two [tex]\( x \)[/tex] tiles and subtract 3 unit tiles.
- The width [tex]\( x + 2 \)[/tex]: One [tex]\( x \)[/tex] tile and add 2 unit tiles.

#### c. Writing an Equation
We have:
[tex]\[ (x + 2) \times (2x - 3) = 2x^2 + x - 6 \][/tex]

### Verification
1. For [tex]\( x^2 - 3x + 2 \)[/tex]:
[tex]\[ (x - 2)(x - 1) = x^2 - x - 2x + 2 = x^2 - 3x + 2 \][/tex]

2. For [tex]\( 2x^2 + x - 6 \)[/tex]:
[tex]\[ (x + 2)(2x - 3) = 2x^2 - 3x + 4x - 6 = 2x^2 + x - 6 \][/tex]

Both factorizations are verified correct.