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Heat and Changes in Matter: Mastery Test
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Type the correct answer in the box. Express your answer to three significant figures.
A2.30-gram ice cube at water's melting point is dropped into a glass of warm juice and gains enough joules of heat to melt completely. If the heat of
fusion is 334 joules/gram, how much energy was absorbed?
The amount of energy absorbed was
joules.
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Answer :

GinnyAnswer
To determine the amount of energy absorbed by a 2.30-gram ice cube melting completely, we use the heat of fusion of ice. The heat of fusion is the amount of energy required to change 1 gram of a substance from solid to liquid at its melting point.

Given:
- Mass of the ice cube ([tex]\( m \)[/tex]) = 2.30 grams
- Heat of fusion of ice ([tex]\( \Delta H_f \)[/tex]) = 334 joules/gram

We use the following formula to calculate the energy ([tex]\( Q \)[/tex]) absorbed:

[tex]\[ Q = m \times \Delta H_f \][/tex]

Substitute the given values into the formula:

[tex]\[ Q = 2.30 \, \text{grams} \times 334 \, \text{joules/gram} \][/tex]

Performing the multiplication:

[tex]\[ Q = 767.9999999999999 \, \text{joules} \][/tex]

Expressing the answer to three significant figures:

[tex]\[ Q \approx 768 \, \text{joules} \][/tex]

Thus, the amount of energy absorbed was [tex]\( 768 \)[/tex] joules.

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