Answer :
Let's solve the problem step-by-step.
Step 1: Setting up the equation
We are given that "10 times, two less than a number, is 90." We need to translate this into a mathematical equation. Let's denote the unknown number by [tex]\( x \)[/tex].
"Two less than a number" is written as [tex]\( x - 2 \)[/tex].
"10 times, two less than a number" means [tex]\( 10 \times (x - 2) \)[/tex].
So, the equation becomes:
[tex]\[ 10 \times (x - 2) = 90 \][/tex]
Step 2: Solving the equation
To isolate [tex]\( x \)[/tex], we first need to get rid of the multiplication by 10. We do this by dividing both sides of the equation by 10:
[tex]\[ x - 2 = \frac{90}{10} \][/tex]
Step 3: Simplifying the right-hand side
Dividing 90 by 10, we get:
[tex]\[ x - 2 = 9.0 \][/tex]
Step 4: Isolating [tex]\( x \)[/tex]
Now, we need to isolate [tex]\( x \)[/tex] by adding 2 to both sides of the equation:
[tex]\[ x = 9.0 + 2 \][/tex]
Step 5: Simplifying the final expression
Adding 2 to 9.0, we get:
[tex]\[ x = 11.0 \][/tex]
Therefore, the number we were looking for is [tex]\( 11.0 \)[/tex].
Step 1: Setting up the equation
We are given that "10 times, two less than a number, is 90." We need to translate this into a mathematical equation. Let's denote the unknown number by [tex]\( x \)[/tex].
"Two less than a number" is written as [tex]\( x - 2 \)[/tex].
"10 times, two less than a number" means [tex]\( 10 \times (x - 2) \)[/tex].
So, the equation becomes:
[tex]\[ 10 \times (x - 2) = 90 \][/tex]
Step 2: Solving the equation
To isolate [tex]\( x \)[/tex], we first need to get rid of the multiplication by 10. We do this by dividing both sides of the equation by 10:
[tex]\[ x - 2 = \frac{90}{10} \][/tex]
Step 3: Simplifying the right-hand side
Dividing 90 by 10, we get:
[tex]\[ x - 2 = 9.0 \][/tex]
Step 4: Isolating [tex]\( x \)[/tex]
Now, we need to isolate [tex]\( x \)[/tex] by adding 2 to both sides of the equation:
[tex]\[ x = 9.0 + 2 \][/tex]
Step 5: Simplifying the final expression
Adding 2 to 9.0, we get:
[tex]\[ x = 11.0 \][/tex]
Therefore, the number we were looking for is [tex]\( 11.0 \)[/tex].