Answer :
To calculate the median of the triangle passing through point A, follow these steps:
1. Identify the Midpoint of Line Segment BC: The median from a vertex (A in this case) of a triangle goes to the midpoint of the opposite side (BC here). To find the midpoint [tex]\( M \)[/tex] of segment BC, we use the midpoint formula:
[tex]\[ M = \left( \frac{x_B + x_C}{2}, \frac{y_B + y_C}{2} \right) \][/tex]
For points B(4, -1) and C(6, 2):
[tex]\[ M_x = \frac{4 + 6}{2} = 5 \][/tex]
[tex]\[ M_y = \frac{-1 + 2}{2} = 0.5 \][/tex]
So, the coordinates of the midpoint [tex]\( M \)[/tex] are [tex]\( (5.0, 0.5) \)[/tex].
2. Calculate the Length of the Median from A to M: The median length is the distance between point A(3, 2) and the midpoint [tex]\( M(5.0, 0.5) \)[/tex]. The distance formula is:
[tex]\[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Substituting the coordinates:
[tex]\[ \text{Distance} = \sqrt{(5.0 - 3)^2 + (0.5 - 2)^2} \][/tex]
[tex]\[ = \sqrt{(2.0)^2 + (-1.5)^2} \][/tex]
[tex]\[ = \sqrt{4 + 2.25} \][/tex]
[tex]\[ = \sqrt{6.25} \][/tex]
[tex]\[ = 2.5 \][/tex]
3. Summary:
- The midpoint of segment BC is [tex]\( (5.0, 0.5) \)[/tex].
- The length of the median from point A to the midpoint [tex]\( M \)[/tex] is 2.5 units.
Therefore, the median from point A(3, 2) of the triangle passes through the midpoint (5.0, 0.5) and the length of this median is 2.5 units.
1. Identify the Midpoint of Line Segment BC: The median from a vertex (A in this case) of a triangle goes to the midpoint of the opposite side (BC here). To find the midpoint [tex]\( M \)[/tex] of segment BC, we use the midpoint formula:
[tex]\[ M = \left( \frac{x_B + x_C}{2}, \frac{y_B + y_C}{2} \right) \][/tex]
For points B(4, -1) and C(6, 2):
[tex]\[ M_x = \frac{4 + 6}{2} = 5 \][/tex]
[tex]\[ M_y = \frac{-1 + 2}{2} = 0.5 \][/tex]
So, the coordinates of the midpoint [tex]\( M \)[/tex] are [tex]\( (5.0, 0.5) \)[/tex].
2. Calculate the Length of the Median from A to M: The median length is the distance between point A(3, 2) and the midpoint [tex]\( M(5.0, 0.5) \)[/tex]. The distance formula is:
[tex]\[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Substituting the coordinates:
[tex]\[ \text{Distance} = \sqrt{(5.0 - 3)^2 + (0.5 - 2)^2} \][/tex]
[tex]\[ = \sqrt{(2.0)^2 + (-1.5)^2} \][/tex]
[tex]\[ = \sqrt{4 + 2.25} \][/tex]
[tex]\[ = \sqrt{6.25} \][/tex]
[tex]\[ = 2.5 \][/tex]
3. Summary:
- The midpoint of segment BC is [tex]\( (5.0, 0.5) \)[/tex].
- The length of the median from point A to the midpoint [tex]\( M \)[/tex] is 2.5 units.
Therefore, the median from point A(3, 2) of the triangle passes through the midpoint (5.0, 0.5) and the length of this median is 2.5 units.