Answer:
x'' = 14.6
Explanation:
The acceleration of the particle is equal to the second derivative of its position function.
The position function is:
x = 4.8t + 7.3t²
The first derivative is:
x' = 4.8 + 14.6t
The second derivative is:
x'' = 14.6
Therefore, the acceleration is constant at 14.6 m/s².